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$\mathrm{NaOH} / \mathrm{H}^{+}$reacts with
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$\mathrm{C}_6 \mathrm{H}_5 \mathrm{OCH}_3$
Dil. sodium hydroxide is used for the hydrolysis of ether.
$\underset{\text { Ether }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{OCH}_3}+\mathrm{H} . \mathrm{OH} \xrightarrow[\mathrm{H}^{+}]{\mathrm{NaOH}}$ $\begin{aligned} & \mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}+\mathrm{CH}_3 \mathrm{OH} \\ & \text { Phenol }\end{aligned}$
$\underset{\text { Ether }}{\mathrm{C}_6 \mathrm{H}_5 \mathrm{OCH}_3}+\mathrm{H} . \mathrm{OH} \xrightarrow[\mathrm{H}^{+}]{\mathrm{NaOH}}$ $\begin{aligned} & \mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}+\mathrm{CH}_3 \mathrm{OH} \\ & \text { Phenol }\end{aligned}$
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