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Nesseler's reagent is
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The correct answer is:
$\mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}$
$2 \mathrm{KI}+\mathrm{HgI}_2 \rightarrow \mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}$
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