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Question: Answered & Verified by Expert
Nickel $(Z=28)$ combines with a uninegative monodentate ligand $\mathrm{X}^{-}$to form a paramagnetic complex $\left[\mathrm{NiX}_4\right]^{2-}$. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively
ChemistryCoordination CompoundsJEE Main
Options:
  • A
    one, tetrahedral
  • B
    two, tetrahedral
  • C
    one, square planar
  • D
    two, square planar
Solution:
1310 Upvotes Verified Answer
The correct answer is:
two, tetrahedral
${ }_{28} \mathrm{Ni}: \ldots \ldots \ldots \mathrm{s}^2, 3 \mathrm{p}^6, 3 \mathrm{~d}^8, 4 \mathrm{~s}^2$
$\mathrm{Ni}^{2+}: 3 \mathrm{~s}^2, 3 \mathrm{p}^6, 3 \mathrm{~d}^8$

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