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Nitrobenzene on reduction using zinc in alkaline medium results in $X$. The number of $\operatorname{sigma}(\sigma)$ and pi $(\pi)$ bonds in $X$ is
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$27 \sigma, 6 \pi$
Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.

Hydrazobenzene $(X)$ contains $27 \sigma$ and $6 \pi$ bonds.

Hydrazobenzene $(X)$ contains $27 \sigma$ and $6 \pi$ bonds.
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