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Nitrobenzene $\left(\mathrm{PhNO}_2\right) \stackrel{\mathrm{Zn}+\mathrm{NH}_4 \mathrm{Cl}}{\longrightarrow} P$ $P$ will be
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$\mathrm{C}_6 \mathrm{H}_5 \mathrm{NHOH}$
In neutral medium, nitrobenzene reduces to phenyl hydroxylamine
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