Number of electrons present in 4 f orbital of Ho 3 + ion is ________ (Given Atomic No. of Ho =67)

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Question: Answered & Verified by Expert

Number of electrons present in

4 f

orbital of

{Ho}^{3 +}

ion is ________ (Given Atomic No. of Ho =67)

Chemistryd and f Block ElementsJEE MainJEE Main 2021 (25 Jul Shift 2)

Solution:

2159 Upvotes Verified Answer

The correct answer is: 10

$Ho = [Xe] 4 f^{11} 6 s^{2}$

${Ho}^{3 +} = [Xe] 4 f^{10}$

so number of $e^{-}$ present in $4 f$ is $10 .$

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