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Number of triangle formed by the lines $x-y+3=0,2 x-y+3=0,3 x-y+2=0$ and $x+y-3=0$ is
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4
Slope of line $x-y+3=0$ is 1 .
Slope of line $2 x-y+3=0$ is 2 .
Slope of line $3 x-y+2=0$ is 3 .
Slope of line $x+y-3=0$ is -1 .
As the slope of lines are different, there are 4 concurrent lines.
Number of triangles formed by these lines
$$
={ }^4 C_3=4
$$
Slope of line $2 x-y+3=0$ is 2 .
Slope of line $3 x-y+2=0$ is 3 .
Slope of line $x+y-3=0$ is -1 .
As the slope of lines are different, there are 4 concurrent lines.
Number of triangles formed by these lines
$$
={ }^4 C_3=4
$$
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