Search any question & find its solution
Question:
Answered & Verified by Expert
On complete combustion, 0.500 g of an organic compound gave 0.150 of carbon dioxide. Determine the percentage composition of carbon in the compound.
Options:
Solution:
2181 Upvotes
Verified Answer
The correct answer is:
\(8.18 \%\)
The required equation is:
Percentage of carbon \(=12 * \mathrm{~m} 2 * 100 / 44 * \mathrm{~m}\)
In this case, \(m=0.500\)
\(\mathrm{m} 2=0.150\)
Substituting in the equation \(\rightarrow\) Percentage of carbon \(=12 * 0.150 * 100 / 44 * 0.500\)
\(=8.18 \%\)
Therefore, the percentage of carbon present in the organic compound is \(8.18 \%\).
Percentage of carbon \(=12 * \mathrm{~m} 2 * 100 / 44 * \mathrm{~m}\)
In this case, \(m=0.500\)
\(\mathrm{m} 2=0.150\)
Substituting in the equation \(\rightarrow\) Percentage of carbon \(=12 * 0.150 * 100 / 44 * 0.500\)
\(=8.18 \%\)
Therefore, the percentage of carbon present in the organic compound is \(8.18 \%\).
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.