On F e 2 O 3 ( s ) + 3 2 C ( s ) → 3 2 C O 2 ( g ) + 2 F e ( s ) ; Δ H ° = + 234.1 k J C ( s ) + O 2 ( g ) → C O 2 ( g ) ; Δ H ° = - 393.5 kJ Use these equations and Δ H ° values to calculate Δ H ° for this reaction 4 F e ( s ) + 3 O 2 ( g ) → 2 F e 2 O 3 ( s )

Question

On F e 2 O 3 ( s ) + 3 2 C ( s ) → 3 2 C O 2 ( g ) + 2 F e ( s ) ; Δ H ° = + 234.1 k J C ( s ) + O 2 ( g ) → C O 2 ( g ) ; Δ H ° = - 393.5 kJ Use these equations and Δ H ° values to calculate Δ H ° for this reaction 4 F e ( s ) + 3 O 2 ( g ) → 2 F e 2 O 3 ( s ), -1648.7 kJ, -1255.3 kJ, -1021.2 kJ, -129.4 kJ

MARKS App · Accepted Answer

2 F e ( s ) + 3 2 C O 2 ( g ) → F e 2 O 3 ( s ) + 3 2 C ( s ) ; Δ H ° = - 234.1 k J …(i) C ( s ) + O 2 ( g ) → C O 2 ( g ) ( Δ H ° = - 393.5 k J ) …(ii) Multiplying eq. (i) by 2 and eq. (ii) by 3 and on adding both equations, we get 4 F e ( s ) + 3 O 2 ( g ) → 2 F e 2 O 3 ( s ) ; Δ H ° = ( - 234.1 × 2 ) + ( - 3 × 393.5 ) = - 1648.7 kJ

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