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Question: Answered & Verified by Expert
On hydrolysis of a "compound", two compounds are obtained, One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution. The "compound" is:
ChemistryAldehydes and KetonesNEETNEET 2013 (Karnataka)
Options:
  • A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NC}$
  • B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CN}$
  • C $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{ON}=\mathrm{O}$
  • D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CON}\left(\mathrm{CH}_3\right)_2$
Solution:
1710 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NC}$
$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NC}+2 \mathrm{H}_2 \mathrm{O} \rightarrow$ $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{NH}_2+\mathrm{HCOOH}$

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