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On moving a charge of $20 \mathrm{C}$ by $2 \mathrm{~cm}, 2 \mathrm{~J}$ of work is done, then the potential difference between the points is
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$0.1 \mathrm{~V}$
Potential difference between two points in an electric field
$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=\frac{W}{q_{0}}$
where $\mathrm{W}$ is work done by moving charge $\mathrm{q}_{0}$ from point $\mathrm{A}$ to $\mathrm{B}$
Here, $\mathrm{W}=2 \mathrm{~J}, \mathrm{q}_{0}=20 \mathrm{c}$
$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=\frac{2}{20}=0.1 \text { volt }$
$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=\frac{W}{q_{0}}$
where $\mathrm{W}$ is work done by moving charge $\mathrm{q}_{0}$ from point $\mathrm{A}$ to $\mathrm{B}$
Here, $\mathrm{W}=2 \mathrm{~J}, \mathrm{q}_{0}=20 \mathrm{c}$
$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=\frac{2}{20}=0.1 \text { volt }$
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