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On treatment of propanone with dilute $\mathrm{Ba}
(\mathrm{OH})_{2}$, the product formed is
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(\mathrm{OH})_{2}$, the product formed is
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The correct answer is:
4-hydroxy-4-methyl-2-pentanone
In Aldol condensation propanone gives diacetone alcohol in presence of $\mathrm{Ba}(\mathrm{OH})_{2}$
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