Potential energy $=$ kinetic energy

$\text{+}\frac{{\text{GM}}_{\text{e}}\text{m}}{\text{R}}\text{=}\frac{\text{1}}{\text{2}}{\text{mv}}_{\text{e}}^{\text{2}}$

Where $m$ is mass of projectile, ${\text{M}}_{\text{e}}$ is mass of earth, $\text{G}$ is gravitational constant, $\text{R}$ is radius.

${\text{v}}_{\text{e}}\text{=}\sqrt{\frac{{\text{2GM}}_{\text{e}}}{{\text{R}}_{\text{e}}}}$

The above formula shows that escape velocity is independent of the mass of the projectile.