One end of a light string is fixed to a clamp on the ground and the other end passes over a fixed frictionless pulley as shown in the figure. It makes an angle of 3 0 ∘ with the ground. The clamp can tolerate a vertical force of 40 N . If a monkey of mass 5 kg were to climb up the rope, then the maximum acceleration in the upward direction with which it can climb safely is ( g = 10 ms − 2 )

Question

One end of a light string is fixed to a clamp on the ground and the other end passes over a fixed frictionless pulley as shown in the figure. It makes an angle of 3 0 ∘ with the ground. The clamp can tolerate a vertical force of 40 N . If a monkey of mass 5 kg were to climb up the rope, then the maximum acceleration in the upward direction with which it can climb safely is ( g = 10 ms − 2 ), 2 ms − 2, 4 ms − 2, 6 ms − 2, 8 ms − 2

MARKS App · Accepted Answer

Let T is tension in the string. Maximum vertical force on clamp, T sin 3 0 ∘ = 40 $ ⇒ ⇒ ​ T ⋅ 2 1 ​ = 40 T = 80 N ​ L e t ma x im u ma cce l er a t i o n o f m o nk ey f ors a t ec l imbin g i s a . T h e n , FB Do f m o nk ey im g src = " h ttp s : // c d n − q u es t i o n − p oo l . g e t ma r k s . a pp / p y q / a p e ​ am ce t /642 E W J n wlE 6 V 6 x eK P d Y f r p x D B cr PE 5 k M u NT 5 T r 6 T i F A . or i g ina l . f u ll s i ze . p n g " > b r > \begin{aligned} & T-m g=m a \Rightarrow a=\frac{T-m g}{m} \ & a=\frac{80-5 	imes 10}{5} \ a= & 6 \mathrm{~m} / \mathrm{s}^2\end{aligned}$

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