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One end of a uniform wire of length $L$ and of weight $W$ is attached rigidly to a point in the roof and a weight ${W}^1$ is suspended from its lower end. If $S$ is the area of cross-section of the wire, the stress in the wire at a height $3 L / 4$ from its lower end is
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The correct answer is:
$\frac{W_1+(3 W / 4)}{S}$
Total force at height $3 L / 4$ from its lower end $=$ Weight suspended + Weight of $3 / 4$ of the chain
$=W_1+(3 W / 4)$
Hence stress$=\frac{W_1+(3 W / 4)}{S}$
$=W_1+(3 W / 4)$
Hence stress$=\frac{W_1+(3 W / 4)}{S}$
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