One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm is introduced into a vessel of volume 1 L . If there is no change in temperature, the final pressure of the mixture of gasses (in atm ) is

Question

One litre of oxygen at a pressure of 1 atm and two litres of nitrogen at a pressure of 0.5 atm is introduced into a vessel of volume 1 L . If there is no change in temperature, the final pressure of the mixture of gasses (in atm ) is, 1.5, 2.5, 2, 4

MARKS App · Accepted Answer

Ideal gas equation is given by, pV = nRT ...(i) For oxygen, p = 1 atm, V = 1 L, n = n O 2 Therefore Eq. (i) becomes 1 × 1 = n O 2 RT ⇒ n O 2 = 1 RT For nitrogen p = 0.5 atm, V = 2 L, n = n N 2 ∴ 0.5 × 2 = n N 2 RT ⇒ n N 2 = 1 RT For mixture of gasses, P mix V mix = n mix RT ⁡ Here n mix = n O 2 + n N 2 ∴ P mix V mix RT ⁡ = 1 RT ⁡ + 1 RT ⇒ P mix V mix = 2

Search any question & find its solution

Looking for more such questions to practice?