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One mole of a diatomic gas does a work $\frac{\mathrm{Q}}{3}$, when the amount of heat supplied is
'Q'. In this process, the molar heat capacity of the gas is
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'Q'. In this process, the molar heat capacity of the gas is
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The correct answer is:
$\frac{15 \mathrm{R}}{4}$
The amount of heat required to increase the internal energy is
$\left(\mathrm{Q}-\frac{\mathrm{Q}}{3}\right)=\frac{2}{3} \mathrm{Q}$
For a diatomic gas, the amount of heat required to increase the internal energy is $C_{v}=\frac{5}{2} R$
$\begin{array}{l}
\therefore \frac{2}{3} Q=\frac{5}{2} R \\
\therefore Q=\frac{15}{4} R
\end{array}$
$\left(\mathrm{Q}-\frac{\mathrm{Q}}{3}\right)=\frac{2}{3} \mathrm{Q}$
For a diatomic gas, the amount of heat required to increase the internal energy is $C_{v}=\frac{5}{2} R$
$\begin{array}{l}
\therefore \frac{2}{3} Q=\frac{5}{2} R \\
\therefore Q=\frac{15}{4} R
\end{array}$
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