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One mole of an ideal gas at an initial temperature of $T K$ does $6 R$ joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is $5 / 3$, the final temperature of gas will be
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$(T-4) K$
$W=\frac{R\left(T_i-T_f\right)}{\gamma-1} \Rightarrow 6 R=\frac{R\left(T-T_f\right)}{\left(\frac{5}{3}-1\right)} \Rightarrow T_f=(T-4) K$
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