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One mole of an ideal monoatomic gas is mixed with one mole of an ideal diatomic gas. The molar specific heat of the mixture at constant volume is (in Calories)
ChemistryStates of MatterJEE Main
Solution:
2724 Upvotes Verified Answer
The correct answer is: 4.00
C v,m = 3 2 R (for monoatomic gas)

C v,m = 5 2 R (for diatomic gas)

for the mixture, (C v,m ) mix = 3 2 R×1+ 5 2 R×1 1+1

=2R

(C v,m ) mix =4cal

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