One mole of ethanol is produced reacting graphite, H 2 and O 2 together. The standard enthalpy of formation is − 277 .7 kJ mol − 1 . Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved.

Question

One mole of ethanol is produced reacting graphite, H 2 and O 2 together. The standard enthalpy of formation is − 277 .7 kJ mol − 1 . Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved., − 277.7 kJ/mol, − 555.4 kJ/mol, − 138.85 kJ/mol, − 69.42 kJ/mol

MARKS App · Accepted Answer

2 C(s) + 1 2 O 2 (g) + 3 H 2 (g) → C 2 H 5 OH(l); ΔH f = − 277 .7 kJ By doubling the reaction, 4 C(s) + O 2 (g) + 6 H 2 (g) → 2 C 2 H 5 OH; ΔH f = 2 × ​ − 277 .7 = − 555.4 kJ

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