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One mole of ideal gas undergoes a linear process as shown in figure below. Its temperature expressed as a function of volume $\mathrm{V}$ is.
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1424 Upvotes
Verified Answer
The correct answer is:
$\frac{P_{0} V}{R}\left(1-\frac{V}{V_{0}}\right)$
$P=\frac{-P_{0}}{V_{0}} V+P_{0}$ $\&$ $P V=n R T$
$$
\begin{array}{l}
P V=n R T \\
\therefore T=\frac{P_{0} V}{R}\left[1-\frac{V}{V_{0}}\right]
\end{array}
$$
$$
\begin{array}{l}
P V=n R T \\
\therefore T=\frac{P_{0} V}{R}\left[1-\frac{V}{V_{0}}\right]
\end{array}
$$
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