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Oxidation number of \(\mathrm{Cr}\) in \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) is
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The correct answer is:
0
CO (carbonyl) is a neutral ligand. So, oxidation number of the metal is metal carbonyl compounds will be 0 (zero).
\(\left[\stackrel{0}{\mathrm{Cr}(\mathrm{CO})_6}\right] \text { : Hexacarbonyl chromium (0). }\)
\(\left[\stackrel{0}{\mathrm{Cr}(\mathrm{CO})_6}\right] \text { : Hexacarbonyl chromium (0). }\)
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