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Oxidation state of oxygen in $\mathrm{F}_2 \mathrm{O}$ is
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The correct answer is:
+2
Let the oxidation state of oxygen in $\mathrm{F}_2 \mathrm{O}$ is $x$.
$\begin{aligned}
& \mathrm{F}_2 \mathrm{O} \\
& 2(-1)+x=0 \\
&-2+x=0 \\
& x=+2
\end{aligned}$
$2(-1)+x=0 \quad(\because \mathrm{F} \text { is more electronegative) }$
$\begin{aligned}
& \mathrm{F}_2 \mathrm{O} \\
& 2(-1)+x=0 \\
&-2+x=0 \\
& x=+2
\end{aligned}$
$2(-1)+x=0 \quad(\because \mathrm{F} \text { is more electronegative) }$
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