[ P d ( F ) ( C l ) ( B r ) ( I ) ] 2 – has 'n' number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy (CFSE) of [Fe(CN) 6 ] n–6 respectively are [Note: Ignore the pairing energy]

Question

[ P d ( F ) ( C l ) ( B r ) ( I ) ] 2 – has 'n' number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy (CFSE) of [Fe(CN) 6 ] n–6 respectively are [Note: Ignore the pairing energy], 5.92 BM and Δ 0, 1.73 BM and –2.0 Δ 0, 2.84 BM and –1.6 Δ 0, 0 BM and –2.4 Δ 0

MARKS App · Accepted Answer

No of G.I in [ P d C l F B r I ] 2 – is 3. Hence n = 3 So [ F e ( C N ) 6 ] n – 6 = [ F e ( C N ) 6 ] – 3 F e 3 + = 3 d 5 4 s 0 As C N - is a strong field ligand. So, according to crystal field theory the configuration is as follows Fe 3 + = t 2 g 2 , 2 , 1 , e g 0 , 0 n = 1 Magnetic moment = n ( n + 2 ) = 1 ( 1 + 2 ) = 3 = 1.73 B.M. CFSE = - 0.4 Δ 0 × n t 2 g + 0.6 Δ 0 × n e g CFSE - 0.4 Δ 0 × 5 = - 2.0 Δ 0

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