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A tertiary alcohol $H$ upon acid catalysed dehydration gives a product $I$. Ozonolysis of I leads to compounds $\mathrm{J}$ and $\mathrm{K}$. Compound $\mathrm{J}$ upon reaction with
$\mathrm{KOH}$ gives benzyl alcohol and a compound $\mathrm{L}$, where $\mathrm{K}$ on reaction with $\mathrm{KOH}$ gives only $M$.
Question:
The structures of compounds $J, K$ and $L$, respectively, are
Options:
A tertiary alcohol $H$ upon acid catalysed dehydration gives a product $I$. Ozonolysis of I leads to compounds $\mathrm{J}$ and $\mathrm{K}$. Compound $\mathrm{J}$ upon reaction with
$\mathrm{KOH}$ gives benzyl alcohol and a compound $\mathrm{L}$, where $\mathrm{K}$ on reaction with $\mathrm{KOH}$ gives only $M$.
Question:
The structures of compounds $J, K$ and $L$, respectively, are
Solution:
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Verified Answer
The correct answer is:
$\mathrm{PhCHO}, \mathrm{PhCOCH}_3$ and $\mathrm{PhCOO}^{-} \mathrm{K}^{+}$
$\mathrm{PhCHO}, \mathrm{PhCOCH}_3$ and $\mathrm{PhCOO}^{-} \mathrm{K}^{+}$
$$
J=\mathrm{PhCH}=\mathrm{O} K=\mathrm{PhCOCH}_3 \quad L=\mathrm{PhCOO}^{-} \mathrm{K}^{+}
$$
J=\mathrm{PhCH}=\mathrm{O} K=\mathrm{PhCOCH}_3 \quad L=\mathrm{PhCOO}^{-} \mathrm{K}^{+}
$$
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