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p-amino-N, N-dimethylaniline is added to a strongly acidic solution of $X$. The resulting solution is treated with a few drops of aqueous solution of $Y$ to yield blue colouration due to the formation of methylene blue. Treatment of the aqueous solution of $Y$ with the reagent potassium hexacyanoferrate(II) leads to the formation of an intense blue precipitate. The precipitate dissolves an excess addition of the reagent. Similarly, treatment of the solution of $Y$ with the solution of potassium hexacyanoferrate(III) leads to a brown colouration due to the formation of $Z$.Question:
The compound $Z$, is
ChemistryAminesJEE Main
Options:
  • A
    $\mathrm{Mg}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
  • B
    $\mathrm{Fe}\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
  • C
    $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$
  • D
    $\mathrm{K}_2 \mathrm{Zn}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$
Solution:
2751 Upvotes Verified Answer
The correct answer is:
$\mathrm{Fe}\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
$p$-amino- $\mathrm{N}$, N-dimethylaniline reacts with sulphide ion $\left(\mathrm{S}^{2-}\right)$ in presence of $\mathrm{Fe}^{3+}$ ion to form blue coloured solution of methylene blue :

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