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The capacitor of capacitance $C$ can be charged (with the help of a resistance $R$ ) by a voltage source $V$, by closing switch $S_1$ while keeping switch $S_2$ open. The capacitor can be connected in series with an inductor $L$ by closing switch $S_2$ and opening $S_1$.
Question:
After the capacitor gets fully charged, $S_1$ is opened and $S_2$ is closed so that the inductor is connected in series with the capacitor. Then,
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The capacitor of capacitance $C$ can be charged (with the help of a resistance $R$ ) by a voltage source $V$, by closing switch $S_1$ while keeping switch $S_2$ open. The capacitor can be connected in series with an inductor $L$ by closing switch $S_2$ and opening $S_1$.
Question:
After the capacitor gets fully charged, $S_1$ is opened and $S_2$ is closed so that the inductor is connected in series with the capacitor. Then,
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Verified Answer
The correct answer is:
at any time $t>0$, maximum instantaneous current in the circuit may $V \sqrt{\frac{C}{L}}$
at any time $t>0$, maximum instantaneous current in the circuit may $V \sqrt{\frac{C}{L}}$
From conservation of energy, $\frac{1}{2} L I_{\max }^2=\frac{1}{2} C V^2$
$$
\therefore \quad I_{\max }=V \sqrt{\frac{C}{L}}
$$
$$
\therefore \quad I_{\max }=V \sqrt{\frac{C}{L}}
$$
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