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Two plane harmonic sound waves are expressed by the equations.
$$
\begin{aligned}
& y_1(x, t)=A \cos (0.5 \pi x-100 \pi t) \\
& y_2(x, t)=A \cos (0.46 \pi x-92 \pi t)
\end{aligned}
$$
(All parameters are in MKS)Question:
What is the speed of the sound?
Options:
Two plane harmonic sound waves are expressed by the equations.
$$
\begin{aligned}
& y_1(x, t)=A \cos (0.5 \pi x-100 \pi t) \\
& y_2(x, t)=A \cos (0.46 \pi x-92 \pi t)
\end{aligned}
$$
(All parameters are in MKS)Question:
What is the speed of the sound?
Solution:
1471 Upvotes
Verified Answer
The correct answer is:
$200 \mathrm{~m} / \mathrm{s}$
$200 \mathrm{~m} / \mathrm{s}$
Speed of wave $v=\frac{\omega}{R}$ or $\quad v=\frac{100 \pi}{0.5 \pi}$ or $\frac{92 \pi}{0.46 \pi}=200 \mathrm{~m} / \mathrm{s}$
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