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When a particle is restricted to move along $x$-axis between $x=0$ and $x=a$, where $a$ is of nanometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends $x=0$ and $x=a$. The wavelength of this standing wave is related to the liner momentum $p$ of the particle according to the de Broglie relation. The energy of the particle of mass $m$ is related to its linear momentum as $E=\frac{p^2}{2 m}$. Thus, the energy of the particle can be denoted by a quantum number $n$ taking values $1,2,3, \ldots(n=1$, called the ground state) corresponding to the number of loops in the standing wave.
Use the model described above to answer the following three questions for a particle moving in the line $x=0$ to $x=a$ [Take $h=6.6 \times 10^{-34} \mathrm{Js}$ and $e=1.6 \times 10^{-19} \mathrm{C}$ ]Question:
The speed of the particle that can take discrete values is proportional to
PhysicsAtomic PhysicsJEE AdvancedJEE Advanced 2009 (Paper 1)
Options:
  • A
    $n^{-3 / 2}$
  • B
    $n^{-1}$
  • C
    $n^{1 / 2}$
  • D
    $n$
Solution:
2553 Upvotes Verified Answer
The correct answer is:
$n$
From Eq. (i)

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