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particle is moving in an elliptical orbit as shown in figure. If $\vec{p}, \vec{L}$ and $\vec{r}$ denote the linear momentum, angular momentum and position vector of the particle (from focus $\mathrm{O}$ ) respectively at a point $\mathrm{A}$, then the direction of $\vec{\alpha}=\overrightarrow{\mathrm{p}} \times \overrightarrow{\mathrm{L}}$ is along
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The correct answer is:
+ ve $x$ axis
$\vec{\alpha}=\overrightarrow{\mathrm{p}} \times \overrightarrow{\mathrm{L}}$
$\vec{L}$ is along Z-axis

$\vec{L}$ is along Z-axis

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