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$\mathrm{pH}$ of soft drink is 3.6. Calculate the concentration of hydrogen ions in it.
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The correct answer is:
$2.51 \times 10^{-4} \mathrm{M}$
$\begin{aligned} & \mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right] \\ & {\left[\mathrm{H}^{+}\right]=10^{-\mathrm{pH}}} \\ & =10^{-3.6} \\ & =10^{-4+0.4} \quad\left(10^{0.4}=2.51\right) \\ & =10^{0.4} \times 10^{-4} \\ & {\left[\mathrm{H}^{+}\right]=2.51 \times 10^{-4} \mathrm{M}}\end{aligned}$
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