Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Pick out the incorrect statement.
ChemistryChemical Bonding and Molecular StructureJEE Main
Options:
  • A The geometry around 'N' atom in trimethylamine is pyramidal
  • B The geometry around N atom in trisilylamine is planar
  • C The nitrogen atom in trimethylamine is sp3 -hybridized; whilst in trisilylamine it is sp2 -hybridized
  • D Trisilylamine has donor properties; whilst trimethylamine has no donor properties
Solution:
2436 Upvotes Verified Answer
The correct answer is: Trisilylamine has donor properties; whilst trimethylamine has no donor properties
In trimethylamine, 'N' atom is sp3 -hybridized.

Due to the presence of lone pair in sp3 -hybrid orbital, the geometry of (CH3)3N becomes pyramidal around nitrogen.

This lone pair of electrons can be donated to electron-deficient species, e.g., (CH3)3NBF3 . This lone pair cannot be transferred to carbon atom, because carbon atom has no d-orbital in its valence shell.
In (SiH3)3N, the 'N' atom is sp2 -hybridized.

The orientation of three sp2 -hybrid orbitals is plane-triangular, therefore, the geometry around 'N' becomes plane-triangular. Here the lone pair of electrons is transferred to vacant d-orbitals to each of three silicon atoms forming pπ-dπ multiple bonds. Consequently, SiH33N has no donor properties. For example
(SiH3)3N+BF3 No reaction.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.