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Positive and negative point charges of equal magnitude are kept at $\left(0,0, \frac{a}{2}\right)$ and $\left(0,0, \frac{-a}{2}\right)$, respectively. The work done by the electric field when another positive point charge is moved from $(-a, 0,0)$ to $(0, a, 0)$ is
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Verified Answer
The correct answer is:
zero
zero
$A \equiv(-a, 0,0) B \equiv(0, a, 0)$
Point charge is moved from $A$ to $B$
$$
\begin{aligned}
V_A & =V_B=0 \\
W & =0
\end{aligned}
$$
$$
\therefore \quad W=0
$$
or the correct option is (c).
Point charge is moved from $A$ to $B$
$$
\begin{aligned}
V_A & =V_B=0 \\
W & =0
\end{aligned}
$$
$$
\therefore \quad W=0
$$
or the correct option is (c).
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