Potassium permanganate works as oxidising agent both in acidic and basic medium. In both state, product obtained by $ \mathrm{KMnO}_{4} $ is respectively

Question

Potassium permanganate works as oxidising agent both in acidic and basic medium. In both state, product obtained by $ \mathrm{KMnO}_{4} $ is respectively, $ \mathrm{MnO}_{2}{ }^{-} $and $ \mathrm{Mn}^{3+} $, $ \mathrm{Mn}^{3+} $ and $ \mathrm{Mn}^{3+} $, $ \mathrm{Mn}^{2+} $ and $ \mathrm{Mn}^{3+} $, $ \mathrm{Mn}^{2+} $ and $ \mathrm{MnO}_{2} $

MARKS App · Accepted Answer

i In alkaline medium, KMnO 4 first reduces to manganate and then insoluble manganese dioxide. Basic medium 2 MnO 4 - + H 2 O → MnO 2 + 2 O - H + 3 O ii In acidic medium: MnO 4 - + 8 H + + 5 e - → Mn + 2 + 4 H 2 O Mn give five electrons oxidizing agent .

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