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Potentiometer wire is $4 \mathrm{~m}$ long and potential difference of $3 \mathrm{~V}$ is maintained between the ends. The e.m.f. of the cell which balances against a length of $100 \mathrm{~cm}$ of the potentiometer wire is
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0.75 V
Potential gradient $=\frac{3}{4} \frac{\mathrm{V}}{\mathrm{m}}$
So, emf against $100 \mathrm{~cm}=\frac{3}{4} \times 1 \mathrm{~V}=0.75 \mathrm{~V}$
So, emf against $100 \mathrm{~cm}=\frac{3}{4} \times 1 \mathrm{~V}=0.75 \mathrm{~V}$
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