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Propyne reacts with $\mathrm{HBr}$ to form Ethe compound $\mathrm{Z}$ is
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3$

This is the electrophilic addition so the product will be 2,2 - dibromo propane.
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