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Question: Answered & Verified by Expert
Propyne reacts with $\mathrm{HBr}$ to form Ethe compound $\mathrm{Z}$ is
ChemistryHydrocarbonsAP EAMCETAP EAMCET 2018 (23 Apr Shift 2)
Options:
  • A $\mathrm{CH}_2(\mathrm{Br}) \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}$
  • B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHBr}_2$
  • C $\mathrm{CH}_3 \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_2 \mathrm{Br}$
  • D $\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3$
Solution:
1051 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_3 \mathrm{CBr}_2 \mathrm{CH}_3$


This is the electrophilic addition so the product will be 2,2 - dibromo propane.

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