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Question: Answered & Verified by Expert
Prove that:
$\cot ^2 \frac{\pi}{6}+\operatorname{cosec} \frac{5 \pi}{6}+3 \tan ^2 \frac{\pi}{6}=6$
MathematicsTrigonometric Functions
Solution:
1759 Upvotes Verified Answer
L.H.S. $=\cot ^2 \frac{\pi}{6}+\operatorname{cosec} \frac{5 \pi}{6}+3 \tan ^2 \frac{\pi}{6}$
$=\left(\cot \frac{\pi}{6}\right)^2+\operatorname{cosec}\left(\pi-\frac{\pi}{6}\right)+3\left(\tan \frac{\pi}{6}\right)^2$
$=(\sqrt{3})^2+\operatorname{cosec} \frac{\pi}{6}+3\left(\frac{1}{\sqrt{3}}\right)^2$
$=3+2+3 \times \frac{1}{3}=3+2+1=6=$ R.H.S.

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