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Prove that the function $f(x)=x^n$ is continuous at $x=n$, where $\boldsymbol{n}$ is a positive integer.
MathematicsContinuity and Differentiability
Solution:
1805 Upvotes Verified Answer
$\mathrm{f}(\mathrm{x})=\mathrm{x}^{\mathrm{n}}$ is a polynomial which is continuous for all $\mathrm{x} \in \mathrm{R}$. Hence $\mathrm{f}$ is continuous at $\mathrm{x}=\mathrm{n}, \mathrm{n} \in \mathrm{N}$.

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