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Question: Answered & Verified by Expert
$\mathrm{R}-\mathrm{OH}+\mathrm{HX} \rightarrow \mathrm{R}-\mathrm{X}+\mathrm{H}_2 \mathrm{O}$
In the above reaction, the reactivity of different alcohols is
ChemistryHaloalkanes and HaloarenesJEE Main
Options:
  • A Tertiary > Secondary > Primary
  • B Tertiary < Secondary < Primary
  • C Tertiary < Secondary > Primary
  • D Secondary < Primary < Tertiary
Solution:
2969 Upvotes Verified Answer
The correct answer is: Tertiary > Secondary > Primary
$R-\mathrm{OX}+\mathrm{HX} \rightarrow \mathrm{R}-\mathrm{X}+\mathrm{H}_2 \mathrm{O}$
Reactivity order of alcohols for this reaction
$3^{\circ}\gt2^{\circ}\gt1^{\circ}$
Reactivity order of halogen acids
$\mathrm{R}-\mathrm{I}\gt\mathrm{R}-\mathrm{Br}\gt\mathrm{R}-\mathrm{Cl}$

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