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Rank the following carbocations in order of stability (1 = most stable)
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The correct answer is:
A → 2, B → 1, C → 3, D → 4
A -2 [3o carbocation with cross conjugation]
B - 1 [2o carbocation with extended conjugation ]
C - 3 [3o carbocation with 4 hyperconjugations and +I of 3 alkyl groups]
D - 4 [2o carbocation with 2 hyperconjugations and +I of 2 alkyl groups]
So order will be
A → 2, B → 1, C → 3, D → 4
B - 1 [2o carbocation with extended conjugation ]
C - 3 [3o carbocation with 4 hyperconjugations and +I of 3 alkyl groups]
D - 4 [2o carbocation with 2 hyperconjugations and +I of 2 alkyl groups]
So order will be
A → 2, B → 1, C → 3, D → 4
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