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Ratio of maximum acceleration to the maximum velocity of a simple harmonic oscillator is
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Verified Answer
The correct answer is:
$\omega$
For SHM, we know that,
Maximum acceleration, $\left|a_{\max }\right|=\omega^2 A$
Maximum velocity, $\left|v_{\max }\right|=\omega A$
where, $\omega=$ angular velocity/frequency
$A=$ amplitude
$\therefore$ According to question, the ratio is
$\frac{\left|a_{\max }\right|}{\left|v_{\max }\right|}=\frac{\omega^2 A}{\omega A}=\omega$
Maximum acceleration, $\left|a_{\max }\right|=\omega^2 A$
Maximum velocity, $\left|v_{\max }\right|=\omega A$
where, $\omega=$ angular velocity/frequency
$A=$ amplitude
$\therefore$ According to question, the ratio is
$\frac{\left|a_{\max }\right|}{\left|v_{\max }\right|}=\frac{\omega^2 A}{\omega A}=\omega$
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