Reduction of acetyl chloride with H 2 in presence of Pd gives, CH 3 COCH 3 , C 2 H 5 OH, CH 3 COOH, CH 3 CHO

CH 3 COCl + H 2 Pd Reduction CH 3 CHO + HCl

Reduction of acetyl chloride with H 2 in presence of Pd gives

Question: Answered & Verified by Expert

Reduction of acetyl chloride with $\mathrm{H}_2$ in presence of $\mathrm{Pd}$ gives

ChemistryHaloalkanes and HaloarenesJEE Main

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Solution:

2479 Upvotes Verified Answer

The correct answer is: $\mathrm{CH}_3 \mathrm{CHO}$

$\mathrm{CH}_3 \mathrm{COCl}+\mathrm{H}_2 \xrightarrow[\text { Reduction }]{\mathrm{Pd}} \mathrm{CH}_3 \mathrm{CHO}+\mathrm{HCl}$

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