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Question: Answered & Verified by Expert
Resistance of a 0.1M KCl solution in a conductance cell is 300 ohm and specific conductance of 0.1M KCl is 1.33 ×10-2ohm-1cm-1 . The resistance of 0.1M NaCl solution in the same cell is 400ohm. The equivalent conductance of the 0.1M NaCl solution (in ohm-1cm2/gmeq.) is
ChemistryElectrochemistryJEE Main
Solution:
1187 Upvotes Verified Answer
The correct answer is: 100
κ=1RlA
i.e. lA=R×κ=300×1.33×10-24.0cm-1
κNaCl=1RlA=1400×4.0
Λm(NaCl)=κ×1000M=4.0400×10000.1=100

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