Root mean square velocity of O 2 at STP is in cm s

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Question: Answered & Verified by Expert

Root mean square velocity of

O_{2}

at STP is

(in \frac{cm}{s})

ChemistryStates of MatterNEET

Options:

A $4.61 \times 1 0^{4}$
B $2.6 \times 1 0^{4}$
C $46.1 \times 1 0^{4}$
D $26.0 \times 1 0^{4}$

Solution:

2487 Upvotes Verified Answer

The correct answer is:

4.61 \times 1 0^{4}

u_{rms} = \sqrt{\frac{3RT}{M}}

= \sqrt{\frac{3×8 {.31×10}^{7} ×273}{32}} = 4 {.61×10}^{4} cm/sec

(at

STP, T = 273 K,

R = 8 .314 × 10^{7} ergs K^{- 1} {mol}^{- 1}

)

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