Search any question & find its solution
Question:
Answered & Verified by Expert
$$
\mathrm{S}+\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow X+Y
$$
Here $X$ is a gas and $Y$ is a liquid and both are triatomic molecules. The number of electron lone pairs present on the central atoms of $X$ and $Y$ are respectively.
Options:
\mathrm{S}+\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow X+Y
$$
Here $X$ is a gas and $Y$ is a liquid and both are triatomic molecules. The number of electron lone pairs present on the central atoms of $X$ and $Y$ are respectively.
Solution:
2866 Upvotes
Verified Answer
The correct answer is:
1, 2
$\mathrm{S}+2 \mathrm{H}_2 \mathrm{SO}_4$ (conc.) $\longrightarrow 3 \mathrm{SO}_2+2 \mathrm{H}_2 \mathrm{O}$
(X) (Y)
As $\mathrm{SO}_2$ has one lone pair of electrons on central atom i.e., sulphur.
And $\mathrm{H}_2 \mathrm{O}$ has two lone pair of electrons on the central atom i.e., oxygen.
(X) (Y)
As $\mathrm{SO}_2$ has one lone pair of electrons on central atom i.e., sulphur.
And $\mathrm{H}_2 \mathrm{O}$ has two lone pair of electrons on the central atom i.e., oxygen.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.