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$(\sec 2 A+1) \sec ^2 A=$
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Verified Answer
The correct answer is:
$2 \sec 2 A$
$(\sec 2 A+1) \sec ^2 A=\left(\frac{1+\tan ^2 A}{1-\tan ^2 A}+1\right)\left(1+\tan ^2 A\right)$
$=\frac{2\left(1+\tan ^2 A\right)}{1-\tan ^2 A}=2 \sec 2 A \text {. }$
$=\frac{2\left(1+\tan ^2 A\right)}{1-\tan ^2 A}=2 \sec 2 A \text {. }$
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