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Question: Answered & Verified by Expert
The above splitting of d-orbitals takes place in the formation of complexes. The above splitting of d-orbitals takes place in the formation of complexes.
ChemistryCoordination CompoundsJEE Main
Options:
  • A tetrahedral
  • B square-planar
  • C octahedral
  • D both tetrahedral and square-planar
Solution:
1072 Upvotes Verified Answer
The correct answer is: octahedral

In an octahedral coordination entity with six ligands surrounding the metal atom/ion, there will be repulsion between the electrons in metal d orbitals and the electrons (or negative charges) of the ligands.

Such a repulsion is more when the metal d orbital is directed towards the ligand than when it is away from the ligand. Thus, the dx2-y2 and dz2 orbitals that point towards the axes along the direction of the ligand will experience more repulsion and will be raised in energy; and the dxy, dyz and dxz orbitals which are directed between the axes will be lowered in energy relative to the average energy in the spherical crystal field.

Thus, the given diagram explains d orbital splitting in an octahedral crystal field.

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