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The accompanying graph of position $x$ versus time $t$ represents the motion of a particle. If $p$ and $q$ are both positive constants, the expression that best describes the acceleration $\alpha$ of the particle is

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The correct answer is:
$a=p-q t$
From graph $\mathrm{V}$ first increases then decreases
Hence $\mathrm{a}$ is earliar positive then negative
$\mathrm{a=P-q t}$
Hence $\mathrm{a}$ is earliar positive then negative
$\mathrm{a=P-q t}$
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