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Question: Answered & Verified by Expert
The angular width of the central maximum in a single slit diffraction pattern is 60° . The width of the slit is 1 μm. The slit is illuminated by monochromatic plane waves. If another slit of the same width is made near it, Young's fringes can be observed on a screen placed at a distance 50cm from the slits. If the observed fringe width is 1cm, what is slit separation distance? (i.e., the distance between the centres of each slit.)
PhysicsWave OpticsJEE MainJEE Main 2018 (08 Apr)
Options:
  • A 100 μm
  • B 25 μm
  • C 50 μm
  • D 75 μm
Solution:
1322 Upvotes Verified Answer
The correct answer is: 25 μm
In diffraction, dsin30°=λλ=d2



Young’s fringe width [ d'- the separation between two slits] 

β=λ×Dd'10-2=d2×50×10-2d'
10-2=10-6×50×10-22×d'd'=25 μm.

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