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Question: Answered & Verified by Expert
The area (in sq. units) of the region enclosed between the parabola y2=2x and the line x+y=4 is ______.
MathematicsArea Under CurvesJEE MainJEE Main 2022 (24 Jun Shift 2)
Solution:
2280 Upvotes Verified Answer
The correct answer is: 18

y2=2x y2=24-y

y2+2y-8=0  y=-4,2

The point of intersection of y2=2x and x+y=4 are 8,-4 and 2,2

Area =-424-y-y22dy =4y-y22-y36-42

=8-2-43--16-8+323

=543=18 Sq.units.

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